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https://expo.survex.com/repositories/troggle/.git
synced 2025-12-17 14:17:12 +00:00
updated scans forlders
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@@ -21,45 +21,126 @@ YEAR_RANGE = (1975, 2050)
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def make_valid_date(walletname, date):
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"""Take whatever garbage some fool has typed in and try to make it into a valid ISO-format date
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Attempts to parse various date string formats into a valid datetime.date object.
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It prioritizes ISO format, then Euro format (dd-mm-yy), then ISO-like (yyyy-m-d)
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using named capture groups for clear parsing.
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Args:
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walletname: Contextual name for logging warnings/errors.
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date: The raw date string input (e.g., '14.12.25', '14/12/2025', '2025-12-1').
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Returns:
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A datetime.date object if successful, otherwise None.
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"""
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# Unify separators: . and / become -
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datestr = date.replace(".", "-").replace("/", "-")
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samedate = None
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# --- 1. Attempt Strict ISO format (yyyy-mm-dd) ---
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try:
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samedate = datetime.date.fromisoformat(datestr)
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return samedate
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except ValueError:
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# Could be in std euro format e.g. 14/07/2023
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match = re.search(r'(\d{1,2})/(\d{1,2})/(\d{2,4})', datestr)
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if match:
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d = int(match.group(1))
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m = int(match.group(2))
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y = int(match.group(3))
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if y<2000:
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y = y + 2000
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try:
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samedate = datetime.date(y, m, d)
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print(f"- - Warning, not in ISO format. '{datestr=}' but we tried to cope: {samedate.isoformat()} {walletname}")
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return samedate
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except:
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print(f"! - Fail, tried to decompose date in dd/mm/yyyy format but failed: {datestr=} ")
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return None
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# probably a single digit day number or month number
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match = re.search(r'(\d{4})-(\d{1,2})-(\d{1,2})', datestr)
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if match:
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y = int(match.group(1))
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m = int(match.group(2))
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d = int(match.group(3))
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try:
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samedate = datetime.date(y, m, d)
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print(f"- - Warning, 1 digit only for month or day '{datestr=}' but we coped: {samedate.isoformat()} ")
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return samedate
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except:
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print(f"! - Fail, tried to decompose date in yyyy-mm-d or yyy-m-dd format but failed: {datestr=} ")
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return None
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pass # Fall through to alternative formats
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if datestr: # might have been None
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if datestr != "None":
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print(f"! - Failed to understand date, none of our tricks worked {datestr=} ")
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return None
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# --- 2. Attempt European/DMY Format (dd-mm-yy or dd-mm-yyyy) ---
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# Example: 14-12-25 or 14-12-2025
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dmy_regex = r'(?P<day>\d{1,2})-(?P<month>\d{1,2})-(?P<year>\d{2,4})'
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match = re.search(dmy_regex, datestr)
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if match:
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data = match.groupdict()
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d = int(data['day'])
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m = int(data['month'])
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y = int(data['year'])
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# Two-digit year handling
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if y < 2000:
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y = y + 2000
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try:
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samedate = datetime.date(y, m, d)
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try:
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swapdate = datetime.date(y, d, m)
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print(f"! - ERROR, not in ISO format. datestr='{datestr}'day and month are ambiguous {samedate.isoformat()} {walletname}")
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except ValueError:
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# swapping day and month does not produce a valid date
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print(f"- - Warning, not in ISO format. datestr='{datestr}' but we tried to guess: {samedate.isoformat()} {walletname}")
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return samedate
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except ValueError:
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print(f"! - Fail, tried to decompose date in dd-mm-yyyy format but failed: datestr='{datestr}'")
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return None # Stop processing
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# --- 3. Attempt ISO-Like Format (yyyy-m-d or yyyy-mm-dd) ---
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# Catches cases where day/month are single digits but format is ISO-like.
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# Example: 2025-1-14 or 2025-12-5
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ymd_regex = r'(?P<year>\d{4})-(?P<month>\d{1,2})-(?P<day>\d{1,2})'
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match = re.search(ymd_regex, datestr)
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if match:
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data = match.groupdict()
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y = int(data['year'])
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m = int(data['month'])
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d = int(data['day'])
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try:
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samedate = datetime.date(y, m, d)
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print(f"- - Warning, 1 digit only for month or day datestr='{datestr}' but we coped: {samedate.isoformat()} {walletname}")
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return samedate
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except ValueError:
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print(f"! - Fail, tried to decompose date in yyyy-m-d format but failed: datestr='{datestr}'")
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return None # Stop processing
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# --- 4. Final Failure Check ---
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if datestr and datestr != "None":
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print(f"! - Failed to understand date, none of our tricks worked datestr='{datestr}'")
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return None
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# def make_valid_date(walletname, date):
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# """Take whatever garbage some fool has typed in and try to make it into a valid ISO-format date
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# """
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# datestr = date.replace(".", "-").replace("/", "-")
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# try:
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# samedate = datetime.date.fromisoformat(datestr)
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# return samedate
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# except ValueError:
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# # Could be in std euro format e.g. 14/07/2023
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# match = re.search(r'(\d{1,2})/(\d{1,2})/(\d{2,4})', datestr)
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# if match:
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# d = int(match.group(1))
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# m = int(match.group(2))
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# y = int(match.group(3))
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# if y<2000:
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# y = y + 2000
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# try:
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# samedate = datetime.date(y, m, d)
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# print(f"- - Warning, not in ISO format. '{datestr=}' but we tried to cope: {samedate.isoformat()} {walletname}")
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# return samedate
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# except:
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# print(f"! - Fail, tried to decompose date in dd/mm/yyyy format but failed: {datestr=} ")
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# return None
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# # probably a single digit day number or month number
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# match = re.search(r'(\d{4})-(\d{1,2})-(\d{1,2})', datestr)
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# if match:
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# y = int(match.group(1))
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# m = int(match.group(2))
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# d = int(match.group(3))
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# try:
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# samedate = datetime.date(y, m, d)
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# print(f"- - Warning, 1 digit only for month or day '{datestr=}' but we coped: {samedate.isoformat()} ")
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# return samedate
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# except:
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# print(f"! - Fail, tried to decompose date in yyyy-mm-d or yyy-m-dd format but failed: {datestr=} ")
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# return None
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# if datestr: # might have been None
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# if datestr != "None":
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# print(f"! - Failed to understand date, none of our tricks worked {datestr=} ")
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# return None
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archaic_wallets = [
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'1984AndysNotebook',
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